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i=0; until (( i >= 3 )); do echo "$i"; (( i++ )); done — but in set -e mode this loop can abort early. Why?

A

The loop condition itself triggers set -e

B

echo fails when given 0

C

until is not affected by set -e

D

(( i++ )) returns a non-zero (failure) status when the result is 0, i.e. on the first iteration where i was 0

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